M37
Riddle / Maths Question
May 20 2015
Comments
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RHP User
11 years ago
Birthday is on the anniversary of the day she was born😊xxFreya
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RHP User
11 years ago
Eliminating May and June is easy. You need to focus on a different property to figure out the second bit, and it can take the brain a little while to change gears. Took me a few minutes.
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RHP User
11 years ago
:)
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RHP User
11 years ago
Freya don't spoil it. As a spoiler, wire your brain to work backwards.
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RHP User
11 years ago
At maths OP..I only read the last part of the question.i wouldn't have a clue...I just stated the bleedin' obvious xx Freya
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RHP User
11 years ago
Slickz will you be giving us the answer? LG
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RHP User
11 years ago
But more of a logic problem. I worked it out quite quickly but I've always enjoyed logic problems (and am generally pretty good at them). As an aside, here's a logic 'joke' to keep you occupied whilst you think about the OP's problem - Three logicians walk into a bar and the barman asks "Does everyone want a drink?". The first logician says "I don't know". The second logician says "I don't know either" and the third logician says "Yes please".
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Aristippusx2
11 years ago
Cheryl is a pain in the ass and doesnt deserve a card nor present!
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RHP User
11 years ago
Quoting 'Leo_girl' Slickz will you be giving us the answer? LG Feel free to post it
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RHP User
11 years ago
the answer: Cherly really wants a 3some
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RHP User
11 years ago
BUT, she wants Bernard and Albert to both go down on her cause she's never experienced two tongues before.
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RHP User
11 years ago
she wants Albert on his back, so she can guide his hard cock in her pussy, and then she wants Bernard to come up from behind and try and fit his cock in DP vagina style How did i reach this conclusion you ask? The way she whispered into albert and bernards ear, she gave very subtle butsuccinct direction.
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RHP User
11 years ago
the answer is June 18
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RHP User
11 years ago
The 8 represents "double penetration"
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RHP User
11 years ago
July 16 - Posted from rhpmobile
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RHP User
11 years ago
Doesn't really deserve a presse - Posted from rhpmobile
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RHP User
11 years ago
If any forumites want be tutored into solving riddle/maths questions, i charge $18/hr
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RHP User
11 years ago
Not a Math problem, its a logic problem. The clue is knowing why Bernard knew when he found out that Albert didn't. Another easy one that is pure and simple maths though it stumped more than 96% of the top math students in a US maths competition. A cardboard tube 15cm long with a circumference of 4cm has a piece of string wrapped evenly around it exactly 5 times starting at one end and ending at the other. How long is the string?
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RHP User
11 years ago
Quoting 'Blindman67' Not a Math problem, its a logic problem. The clue is knowing why Bernard knew when he found out that Albert didn't. Another easy one that is pure and simple maths though it stumped more than 96% of the top math students in a US maths competition. A cardboard tube 15cm long with a circumference of 4cm has a piece of string wrapped evenly around it exactly 5 times starting at one end and ending at the other. How long is the string? Ans: "How long is the piece of string?"
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RHP User
11 years ago
Quoting 'Blindman67' Not a Math problem, its a logic problem. The clue is knowing why Bernard knew when he found out that Albert didn't. Another easy one that is pure and simple maths though it stumped more than 96% of the top math students in a US maths competition. A cardboard tube 15cm long with a circumference of 4cm has a piece of string wrapped evenly around it exactly 5 times starting at one end and ending at the other. How long is the string? No one said you could not post the answer, so I would say 35cm
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RHP User
11 years ago
The string is 25cm long. Imagine if you unroll it. You end up with a triangle 20cm along the base (5 times 4 cm) & 15cm up the side. The string forms the hypotenuse. So from Pythagoras, hypot. = square root of sum of square of both sides of right angled triangle... Sqrt( (20 x 20) + (15 X15) ) Sqrt (400 + 225) Sqrt (625) 25 No doubt that's made all you ladies feel pretty horny ! (Just hoping I got the answer correct)
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RHP User
11 years ago
Quoting 'Blindman67' A cardboard tube 15cm long with a circumference of 4cm has a piece of string wrapped evenly around it exactly 5 times starting at one end and ending at the other. How long is the string? Twice as long as half it's length of course
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RHP User
11 years ago
Quoting 'Single_Guy4U' Quoting 'Blindman67' Not a Math problem, its a logic problem. The clue is knowing why Bernard knew when he found out that Albert didn't. Another easy one that is pure and simple maths though it stumped more than 96% of the top math students in a US maths competition. A cardboard tube 15cm long with a circumference of 4cm has a piece of string wrapped evenly around it exactly 5 times starting at one end and ending at the other. How long is the string? No one said you could not post the answer, so I would say 35cm Sorry Single_Guy that is not the correct answer. This problem is very simple yet it has a habit of being miss understood.
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RHP User
11 years ago
Quoting 'Blindman67'Not a Math problem, its a logic problem. The clue is knowing why Bernard knew when he found out that Albert didn't. Another easy one that is pure and simple maths though it stumped more than 96% of the top math students in a US maths competition. A cardboard tube 15cm long with a circumference of 4cm has a piece of string wrapped evenly around it exactly 5 times starting at one end and ending at the other. How long is the string? for the first, I used the same approach as xtpomg (wrapping it lengthwise wouldn't satisfy the condition that it goes from one end to the other and is done evenly)
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RHP User
11 years ago
Xtpomg Full marks for the correct answer and the showing your method. Though I would have had it as 25 = 5*sqrt((15/5)*(15/5)+4*4);The right triangle makes a perfect integer triangle with sides 3, 4, and 5 units in length. 5 is the square root of the sum of the two sides squared. 5 = sqrt( 3*3 + 4*4 ) = sqrt( 9+16) = sqrt (25); Any LEGO fans will know how important unit right triangles are in construction as you can not brace along fractions of a stud. What drove the Pythagoreans mad and by some accounts murderous was that that the right triangle with sides 1 by 1 has a hypotenuse that is an irrational number. Such a number can never be written, or expressed as the ratio of two integers, it can only ever be an approximation. This did not sit well with the Greeks as they believed in a perfect mathematical universe and dealt with it by killing some who foolishly reminded them of the square root of two.. Cantor a great in the math world used irrational numbers to prove that infinity is actually not a single entity. There can be infinities that are larger than others. For all rational numbers one can always draw a one to one relation between any two, but when you try to do the same for irrational numbers you can always find a number that will break the relationship. The set of rational numbers is infinite is size, yet the set of irrational numbers is greater, for each rational number you can always find more than one irrational. Not all infinities are the same. The string in this case is 25cm long had the tube been 5cm long and 1cm in circumference then you could only ever have made an approximation. The question is solvable using calculus as well.
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RHP User
11 years ago
So says the 47 year old Perth man to the 46 year old Perth man. <sigh> :-(
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RHP User
11 years ago
is it July 14? LG
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RHP User
11 years ago
Albert gives it away when he tells Bernard he doesn't know either. Enjoy these types of puzzles - Posted from rhpmobile
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RHP User
11 years ago
Quoting 'Leo_girl' is it July 14? LG No it's not
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RHP User
11 years ago
A clue for those still trying the birthday puzzel as its dragging on and the OP is MIACheryl did not want to make it easy for the guys to get the answer. As she gave one of them the date and for some dates it would have been a give away so eliminate those dates.
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RHP User
11 years ago
Alot of nerds will just use google to find the answer
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RHP User
11 years ago
At least post up an original that nobody has seen before.
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RHP User
11 years ago
At least post up an original that nobody has seen before.
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RHP User
11 years ago
is my guess
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RHP User
11 years ago
the real answer is july 16 for working out see http://www.nytimes.com/2015/04/15/science/answer-to-the-singapore-math-problem-cheryl-birthday.html
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RHP User
11 years ago
Quoting 'Blindman67' Not a Math problem, its a logic problem. The clue is knowing why Bernard knew when he found out that Albert didn't. Another easy one that is pure and simple maths though it stumped more than 96% of the top math students in a US maths competition. A cardboard tube 15cm long with a circumference of 4cm has a piece of string wrapped evenly around it exactly 5 times starting at one end and ending at the other. How long is the string? the answer to this quiz: http://io9.com/ready-this-simple-puzzle-once-stumped-96-of-americas-1698814691
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RHP User
11 years ago
15cmx2x5 + 4x2x5 is the answer. Boom
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RHP User
11 years ago
Actually have to find radius from Circ. On a train but yeh instead of 4 have 2x radius. using 2Pi*R
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RHP User
11 years ago
Ooo actually if it's a tube you don't need to add 2xDiameterx5. so my final answer is 5x15 + 5xthickness of cardboard (if u want to be technical). Answer is probs 75cm
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RHP User
11 years ago
LOL sorry Slickz way out. I gave the circumference as 4cm not the radius or diameter so no need to use PI. The problem is solved by imaging cutting the tube length wise and laying it out flat. The string would then trace out 5 triangles on the flattened tube 4cm by 15cm each right triangle would then have sides of 3cm and 4cm. To find the hypotenuse its the square root of the sum of the two sides squared, 3*3 = 9 and 4*4 = 16 add them to get 25 and find the square root is 5cm as there are 5 triangle multiply by 5 to get 25cm long. The question is designed to not need a calculator and avoid fractions.
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RHP User
11 years ago
Quoting 'Slickz' Ooo actually if it's a tube you don't need to add 2xDiameterx5. so my final answer is 5x15 + 5xthickness of cardboard (if u want to be technical). Answer is probs 75cm Slickz, I posted earlier about this approach - the problems states that it is evenly wrapped around, and ends up at the opposite end to which it started. So you can't wrap 5 times around evenly - going "around" the tube counting one full circuit would end up at the same end you started from, doing this five times would still be "even", but you wouldn't be at the far end. So you'd need a half time around to go to the other end - this wouldn't be 'evenly' wrapped. Going back down the middle of the tube uses less string, but is essentially the same situation, you won't be "evenly wrapped" and also back at the other end of the tube unless you spiral it. (Though I think the spiral would only be "evenly wrapped" for certain length, diameter and turn counts)
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RHP User
11 years ago
A farmer is walking between two villages carrying a bucket full of potatoes. Every 1/4 of a mile he puts a potatoe on the ground. How long does it take him to walk back ?
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Genius_Ironman
11 years ago
Bill wants to buy a male Doberman puppy. He notices an ad on Ebay, saying "Two Doberman puppies for sale". He rings, and asks "is at least one dog a male?" The answer is "Yes". What is the probability that the other dog is also male?
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RHP User
11 years ago
said it's not may is wrong
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RHP User
11 years ago
got to be may 19
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RHP User
11 years ago
To find a woman who tells the truth about her age .LOL I think I know the answer but it took me some time and it annoyed me.
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funtwo13
11 years ago
OMG - why am I even wasting my time on this stuff? It drives me insane! Ive googled the answer (thanks for the help, guys ) but is still doesn't make sense! Going back to doing something ever so much more stimulating and fun . XXXMrs Funtwo
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RHP User
11 years ago
Quoting 'S_OnTheLoose' Quoting 'Slickz' Ooo actually if it's a tube you don't need to add 2xDiameterx5. so my final answer is 5x15 + 5xthickness of cardboard (if u want to be technical). Answer is probs 75cm Slickz, I posted earlier about this approach - the problems states that it is evenly wrapped around, and ends up at the opposite end to which it started. So you can't wrap 5 times around evenly - going "around" the tube counting one full circuit would end up at the same end you started from, doing this five times would still be "even", but you wouldn't be at the far end. So you'd need a half time around to go to the other end - this wouldn't be 'evenly' wrapped. Going back down the middle of the tube uses less string, but is essentially the same situation, you won't be "evenly wrapped" and also back at the other end of the tube unless you spiral it. (Though I think the spiral would only be "evenly wrapped" for certain length, diameter and turn counts) Yep I figured it out when I got home from work last night. You have to make triangles.
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RHP User
11 years ago
I was a bit confused about how the string was wrapped around the tube but what BlindMan meant was you start with the piece of string at one end and wrap it around (literally 'around' - not length ways) the tube as you work your way down towards the other end. If RHP's formatting lets me I'll try and show you in my best ascii art interpretation - ________________ |\ \ \ \ \ | | \ \ \ \ \ | |_\__ \__ \__ \__ \|
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RHP User
11 years ago
That didn't work properly
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RHP User
11 years ago
Quoting 'Genius_Ironman' Bill wants to buy a male Doberman puppy. He notices an ad on Ebay, saying "Two Doberman puppies for sale". He rings, and asks "is at least one dog a male?" The answer is "Yes". What is the probability that the other dog is also male? Assuming that there is no influance from external sources the odds of a dog being male is 1 in 2 but that may not mean that is true in this case as we are considering the two dogs. To solve one must thus look at all the possibilities Male MaleMale FemaleFemale MaleFemale Female That gives us 4 possible combinations.We exclude the 2 female dogs as the owner would not have replied yes.That gives us 3 situations where a dog is male. Of those three only one has a second male.My answer is the odds of the second dog being male is 1 in 3 or 33.33...% chance.
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RHP User
11 years ago
Being on RHP It's just a numbers game...
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RHP User
11 years ago
I remember doing this question in High School. It's a good problem for those who want to get their head around probability calcs. Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?
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RHP User
11 years ago
Quoting 'Slickz' I remember doing this question in High School. It's a good problem for those who want to get their head around probability calcs. Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice? The Monty Hall problem, I wont answer as I know this one very well. In this one as with the dogs the odds are modified due to the knowledge gathered. In the dogs knowing that two female dogs was not part of the final selection changed the odds of the other being male. Here the host knows where the car is and by opening another door the host changes the odds. This one has seen much study by some very well regarded mathematicians. Probability and statistics is relatively new to maths with the first real study of odds and probability being in 1657 only a few decades before Isaac Newton introduced calculus the the world. Probability was not really formalized in mathematical terms till the 18th century. We could calculate the orbits of the planets a century before we could calculate the odds of a roll of the dice. It is still very poorly understood by the general public.
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MsJonesy
11 years ago
is my worst nightmare. Can I just sit in the corner with a good book and skip maths altogether?
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RHP User
11 years ago
Quoting 'Genius_Ironman' Bill wants to buy a male Doberman puppy. He notices an ad on Ebay, saying "Two Doberman puppies for sale". He rings, and asks "is at least one dog a male?" The answer is "Yes". What is the probability that the other dog is also male? If a woman has four sons, what are the odds her fifth child will be a girl? 50%.
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RHP User
11 years ago
Quoting 'Blindman67' To solve one must thus look at all the possibilities Male MaleMale FemaleFemale MaleFemale Female That gives us 4 possible combinations. That would have worked if the question had been "There are two dogs, what are the odds both are male?" The sex of only one dog is in question here, so there are only two options, male or female. I think anyway.
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RHP User
11 years ago
I had a re read. As there is no mention which is male just that there is a male this gives a bias toward the females and eliminates the possibility of there being only females. There are only 3 possible combinations where at least one can be male. Of that only 1 can answer yes the other is male. Hence 1/3. Though I can not be 100% sure my answer is correct. Change you question and remove the "next" as the dog question did not include order.A woman has 4 boys what is the odds that another child would be a girl. 5 in 6 or just over 83% The subtly is in the question, removing the order from the question changes the way the odds are calculated. Below are all possible combinations of boy girl. Which is 2 (boy or girl) to the power of 5 children 2^5 = 32 We have to assume that each possibility has equal probability of happening 1 in 32. If you ignore the fact that the woman has had 4 boys there is equal chance of a girl or boy. But we do not ignore the other 4 we can only use the outcomes that have 4 or more boys. so we eliminate all other possibilities. Of the five remaining combinations only one can be anothe boy. The odds that the one of the children is another Boy is 1/6. It seems counter intuitive, but that is how its doneGGGGGBGGGGGBGGGBBGGGGGBGGBGBGGGBBGGBBBGGGGGBGBGGBGGBGBGBBGBGGGBBGBGBBGGBBBGBBBBG <--GGGGGBBGGGBGBGGBBBGGBGGBGBBGBGBGBBGBBBBGB <--GGGGBBBGGBBGBGBBBBGBB <--GGGBBBBGBBB <--GGBBBB <--GBBBBB <-- B
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RHP User
11 years ago
I have $20. She has $5. Therefore she has $25, that's how maths works. 😜
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